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No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Solution The correct option is A 365The least number that is exactly divisible by 12, 15,18 and 24 is the LCM of the three numbers.212,15,18,2426,15,9,1223,15,9,633,15,9,331,5,3,151,5,1,11,1,1,1 L.C.M. of 12, 16, 24, 36 =2×2×2×3×3×5=360 360 is the least number which when divided by the given numbers will leave remainder 0 in each case.Therefore, the least number which when divided by 12, 15, 18 and 24 leaves a remainder 5 in each case = 360 + 5 = 365Nội dung chính
Find the least number which when divided by 6, 15 and 18, leave remainder 5 in each case. Solution Find the LCM of given numbersGiven numbers: 6,15,18 can be written in prime factors as6=2×315=3×5and18=2×3×3∴LCM6,15,18=2×3×3×5=90.The number that is 5 more than the LCM of the given numbers will leave a remainder of 5 when divided by these numbers.So, the required number is 90+5=95.Therefore, when 95 is divided by the given numbers, it will leave a remainder of 5.Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case. Nội dung chính
SolutionWe first find the LCM of 12, 16, 24, and 36 as follows: Thus, LCM = 2 × 2 × 2 × 2 × 3 × 3 = 144 144 is the least number which when divided by the given numbers will leave remainder 0 in each case. But we need the least number that leaves remainder 7in each case. The required least number = 144 + 7 = 151. Concept: Lowest Common Multiple Is there an error in this question or solution? Solution: We will be using the concept of LCM(Least Common Multiple) to solve this. To determine the least number which when divided by 6, 15, and 18 leave the remainder 5 in each case,we need to find the LCM of the three given numbers. Since, the LCM obtained will be the smallest common multiple of all the three numbers 6, 15, and 18, after getting LCM we need to add 5 to it so as to get 5 as a remainder. Let's find the LCM of 6, 5 and 18 as shown below. Therefore, LCM of 6, 15 and 18 = 2 × 3 × 3 × 5 = 90. Thus we can see that, 90 is the least number exactly divisible by 6, 15, and 18. To get a remainder 5, we need to add 5 to the LCM. ⇒ 90 + 5 = 95. Thus, when 95 is divided by 6, 15, and 18 we get a remainder of 5 in each case. Hence, the required number for the given problem is 95. You can also use the LCM Calculator to solve this. NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.7 Question 8 Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each caseSummary: The least number which when divided by 6, 15, and 18 leaving a remainder of 5 in each case will be 95. ☛ Related Questions:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.This question was previously asked in SSC CGL Tier 2 Quant Previous Paper 3 (Held On: 18 November 2020) View all SSC CGL Papers >
Answer (Detailed Solution Below)Option 4 : 364 Free History of Indian Constitution 15 Questions 15 Marks 9 Mins Concept Used- The least number which is divisible by several numbers is the LCM of such numbers. Calculation- The least number which is divisible by 12, 18, 24 and 30 = LCM of 12, 18, 24 and 30 ⇒ 360 Now the least number which leaves remainder as 4 when divided by 12, 18, 24 and 30 = 360 + 4 ⇒ 364 Now, 364 is divisible by 7. ∴ 364 is the required number. Latest MP Police Constable Updates Last updated on Sep 22, 2022 The Madhya Pradesh Police has released the revised schedule for the Preliminary Eligibility Test (PET) of the Madhya Pradesh Police Constable exam on 20th May 2022. The exam was cancelled in view of the extreme heatwave conditions in Madhya Pradesh. The PET is now scheduled for 6 June onwards. A total of 4000 vacancies are to be filled by the MP Police Constable Recruitment 2022. The candidates should go through the MP Police Constable Syllabus and Exam Pattern to have an idea of the requirements of the exam. Stay updated with Quantitative Aptitude questions & answers with Testbook. Know more about Number System and ace the concept of LCM and HCF and LCM 60149139180 Answer : B Solution : Least number = LCM of `(12,18,16,36) + 5` <br> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/ARH_PSTET_I_SP_16_E03_010_S01.png" width="80%"> What is the least number which when divided by 12 16 24 36 leaves a remainder 7 in each case?Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151. What is the least number which when divided by 12 18 36?Answer: The least number which when divided by 12,18,36,45 leaves 8,14,32,41 remainder respectively is 176. What is the least number which when divided by 12 16 and 18 leaves 5 as remainder in each case?∴ The smallest number which when divided by 12,16 and 18 gives remainder 5 is 149. What is the least possible number when divided by 12 16 18 and 20 leaves 11 as remainder ?Answer: Required Number is 1461. Which is the least number which when divided by 12 and 16?The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is : - GKToday. = 48 – 7 = 41. Hence option [C] is correct answer. What is the least number which when divided by 12 18 & 24 leaves a remainder 5 in each case & it is also divisible by 13?Therefore, the least number which when divided by 12, 15, 18 and 24 leaves a remainder 5 in each case = 360 + 5 = 365. Q. What is the least number which when divided by 12 14 and 16 leaves a remainder of 7?Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151. What is the least number when divided by 16 18 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder?By putting x = 1, 2, 3 and putting the value of x = 5, the required number comes to be 18004. What is the least number which when divided by 12 18 & 24 leaves a remainder 5 in each case & it is also divisible by 13?Therefore, the least number which when divided by 12, 15, 18 and 24 leaves a remainder 5 in each case = 360 + 5 = 365. Q.
Which is the least number which when divided by 12 and 16?The smallest number, which when divided by 12 and 16 leaves remaining 5 and 9 respectively, is : - GKToday. = 48 – 7 = 41. Hence option [C] is correct answer.
What is the least number when divided by 8 12/16 leaves remainder?The least number which when divided by 8, 12, 16, and 24 leave a remainder of 4 in each case is: 64.
What is the least number when divided by 16 18 and 25 leaves 4 as remainder in each case but when divided by 7 leaves no remainder?By putting x = 1, 2, 3 and putting the value of x = 5, the required number comes to be 18004.
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