In order to find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 Show
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We get 285 – 9 = 276 1249 – 7 = 1242 So the required number = HCF of 276 and 1242 By resolving the required number into prime factors we get 276 = 2 × 2 × 3 × 23 1242 = 2 × 3 × 3 × 3 × 23 So the HCF of 276 and 1242 = 2 × 3 × 23 = 138 Therefore, the greatest number which divides 285 and 1249 leaving remainders 9 and 7 is 138. Answer Verified Hint: Subtracting the remainder from the given numbers and finding the highest common factor gives the greatest number. That gives us the largest number. We have to subtract because above it was mentioned that the number
divides the given number and leaves a remainder that means remainder is subtracted to get the number which is divisible by the largest number.Complete step-by-step solution - Note: This is a direct problem with finding the greatest number by writing the factors. The basic step here is to subtract the remainder and then find the greatest number. Highest common factor gives the greatest number that divides the given number. Find The Largest 2 Digit Number That Divides 673 And 865 Leaving Remainder 1 In Each Maths Q&A Solution Solve for the HCF to get the required number,Finding factors for the first number, 673-1=672 (As the remainder is 1.)Factorize 672⇒672=2×2×2×2×2×3×7Finding factors for the second number,865-1=864(Remainder is 1)Factorize 864⇒864=2×2×2×2×2×3×3×3The HCF of 672 and 864 isHC F(672,864)=2×2×2×2×2 ×3⇒HCF(672,864)=96Hence, the largest two-digit number that divides 673 and 865 by leaving the remainder 1 in each is 96.Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Solution The correct option is A5To find the largest number that divides 679 and 599 leaving remainder 4 in each case We need to find the largest number that divides 679-4=675 and 599-4 = 595 i.e the the HCF of 675 and 595 HCF(675,595) =5SolveTextbooksQuestion PapersWhat is the largest number that divides 445 572 and 699 and leaves remainder of 4/5 and 6 respectively?Answer: 63 is the largest divisor that will give the desired remainders. Q. Find the greatest number that will divide 445, 572 and 699, leaving remainders 4, 5, 6 respectively. What is the greatest number that will divide 6844 and 6123 and leave remainder 4 and 3 respectively?We need the highest number that divides 6844 and 6123 and leave remainders 4 and 3 respectively. HCF = 2 × 2 × 2 × 3 × 3 × 5 = 360. Therefore, the number is 360. What is the largest number which divides 129 and 545 leaving remainder 3 and 5 respectively?Consider HCF be x. In order to make 129 and 545 completely divisible by x, we need to deduct the remainder 3 and 5 from the cases. ∴ largest number which divides 126 and 540 leaving remainder 3 and 5 in case is 18. What is the largest number which divides 70 and 123 leaving remainder 5 and 8 respectively?Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 and 8 respectively. What is the biggest 2 digit number divisible by10?LCM of 5 and 10 = 10. So any number divisible by 5 and 10 is a multiple of 10. 2 digit multiples of 10 = { 10, 20, 30, 40, 50, 60, 70, 80, 90 }. Highest 2 digit multiple of 10 is 90.
How to find the largest number which divides two numbers?The correct option is A True
Greatest Common Factor or Greatest Common Divisor (GCD) of two or more numbers is the (largest/smallest) number that divides evenly into each of the given numbers.
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