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- Test: Factors & Multiples
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- Related TestStep 1: Prime factorisation of the given numbers25=5×540=2 ×2×2×560=2×2×3×5Step 2: Finding L.C.M. L.C.M of 25,40and 60=2×2×2×3×5×5 =600The required number is 7 more than the L.C.M, i.e., 600+7=607Therefore the least number which when divided by 25,40and 60 leaves remainder 7in each case is 607.Related VideosWhat is the smallest number
which when divided by 25 40 and 60 leaves remainder 7 in each case?Which when divided by 25 40 and 60 leaves 9 as the remainder in each case?What is the smallest non zero square number which divisible by 25 40 and 60?What is the smallest of all the natural numbers which leaves a remainder of 7?
Answers
Related Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case?a)607 b)608c)609 d)610Correct answer is option 'A'. Can you explain this answer?
5×4×5×2×3=600
Required numbers is 600+7=607
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Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case?a)607 b)608c)609 d)610Correct answer is option 'A'. Can you explain this answer? for Class 5 2022 is part of Class 5 preparation. The Question and answers have been prepared according to the Class 5 exam syllabus. Information about Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case?a)607 b)608c)609 d)610Correct answer is
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5×4×5×2×3=600Required numbers is600+7=607
Solution
Step 1: Prime factorisation of the given numbers25=5×540=2 ×2×2×560=2×2×3×5Step 2: Finding L.C.M. L.C.M of 25,40and 60=2×2×2×3×5×5 =600The required number is 7 more than the L.C.M, i.e., 600+7=607Therefore the least number which when divided by 25,40and 60 leaves remainder 7in each case is 607.
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Updated On: 27-06-2022
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What is the smallest number which when divided by 25 40 and 60 leaves remainder 7 in each case?
Therefore the least number which when divided by 25 , 40 and 60 leaves remainder 7 in each case is 607 .
Which when divided by 25 40 and 60 leaves 9 as the remainder in each case?
Hence, 609 is the least number which when divided by 25, 40 and 60 leaves 9 as remainder in each case.
What is the smallest non zero square number which divisible by 25 40 and 60?
Explanation: The LCM of three non-zero integers, a(25), b(40), and c(60), is the smallest positive integer m(600) that is divisible by a(25), b(40), and c(60) without any remainder.
What is the smallest of all the natural numbers which leaves a remainder of 7?
Thus, we have [3640+7=3647]. Hence, the smallest number which leaves a remainder [7] when divided by [35,56,91] is [3647]. ... What is the smallest number that, when divided by 35,56. and 91. leaves remainder of 7. in each case?. Tải thêm tài liệu liên quan đến nội dung bài viết Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case
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