The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

Question 1 Playing with numbers Exercise 2.10

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The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

Answer:

Prime factorization of

24 = 2 × 2 × 2 × 3

36 = 2 × 2 × 3 × 3

54 = 2 × 3 × 3 × 3

So the required LCM = 2 × 2 × 2 × 3 × 3 × 3 = 216

The smallest number which is exactly divisible by 24, 36 and 54 is 216

In order to get remainder as 5

Required smallest number = 216 + 5 = 221

Therefore, the smallest number which when divided by 24, 26 and 54 gives a remainder of 5 each time is 221.

Video transcript

"Welcome to lido homework. My name is leonie Rolla and in today's Q&A video. We are going to solve a word problem. So let us repeat the question together. What is the smallest number which when divided by 24 36 and 54 gives a remainder of 5 each time. So as you can see that in the question, we are supposed to find s smallest number and that smallest number should be common right foot. Before 36 and 54 in what way says in such a way that whenever we divide that number by 24 we divide that number by 36 and we divide that number by 50 for we should get a remainder of 5 each time. So let us think about it, right? How can we do this? So before I start finding that number for who's the remainder after dividing by 24 36 54 we get the remainder as 5 let us And a number that is divisible by 24 by 36 by 54 right? In fact, let us find the least common number that is or least common multiple of 24 36 and 54. So right now what I'm going to do is I'm going to find the LCM of 24 36 and 54. Let us see how we can do that. So 24 the prime factorization of 24 is as follows 212 size twenty four to six Squeals to these ice 6 similarly for 36 it is going to be to 80s is thirty six to nine size 1833 size 9 similarly for 54 2 to the 4 to 7 of 14 three nines ice 27 3 3 0 is 9 therefore 24 can be written as 2 into 2 into 2 into 3. Similarly 36 can be written as 2 into 2 2 into 3 into 3 and few to 4 can be written as 2 into 3 into 3 into 3, right? Let us first find what are the comments here? So we have two two two common and we have three three three common and it has we have three and three common in the second number and the first and second number. We have two common. Therefore. The LCM e is 2/3 This to this tree and the leftovers in the first case that is two in the second case the third case that is three, right? So let us try to multiply this and see how much we will get to these I-66 to size 12 12 into 3 is 36 their son into here, right? So till here it is 36 and 2 into 3 is 6 now, let us see how we can find the value of 36 into 6. So 6 is 6 3 9 6 3 is 18 216 there for two and six is the least common multiple for 24 36 and 54. But the question is not asking us to find the least common multiple. In fact, the question is asking us to find the smallest number the least number which when divided by 24 36 and 54 which will give me five. Now if I divide 2 and 6 by 24 I'm going to get the remainder is 0 similarly if I divide 2 and 6 by 36 I'm going to get the remainder is 0 and also if I divide 216 by 51, I'm going to get the remainder as 0 right. So now what am I supposed to do so that I'll get the remainder as five. My load sticks tells me that I just need to add 5 to 216 which will give me 2 to 1 therefore if I divide 2 to 1 by 24, I'll get the remainder as five. Strangest chicken legs two to one. Let us try to divide it by 24 so we can know that 24 how many times will give me 2 to 1 any idea there is none, right? So let us find just next to that let us find the multiple of 20 for this next 2 to 21 and it will give me it might be to the 6 from here. Also. I can find it very easily to the for photos of eight a tree size 24. They did you guess so if I divide. Let's say Let's Take by 9:00. Okay, 9:00 for size 36 399 to jst in 216 Creek. So if I multiply 24 into 9, I will get it as 216 and I'm getting the remainder is 5 isn't it similarly when I divide 2 to 1 by 36 and when I divide 54 by 3054 221 by 54R still get the remainder is 5 and that is what the question is asking us. Hence now. Now we can conclude that. Hence. 221 is the required smallest number, right? It is the required smallest number. That's it. So what is the Mercury since this is a word problem. You have to give the answer in terms of statements as well. Okay you to give the answer in terms of statement only. Okay guys, that's it for today's Q&A video. If there is any doubt, please do comment below and if you liked the video and for such upcoming videos to subscribe to Lido "

The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is
The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

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LCM of 16, 24, 36, and 54 is the smallest number among all common multiples of 16, 24, 36, and 54. The first few multiples of 16, 24, 36, and 54 are (16, 32, 48, 64, 80 . . .), (24, 48, 72, 96, 120 . . .), (36, 72, 108, 144, 180 . . .), and (54, 108, 162, 216, 270 . . .) respectively. There are 3 commonly used methods to find LCM of 16, 24, 36, 54 - by prime factorization, by division method, and by listing multiples.

What is the LCM of 16, 24, 36, and 54?

Answer: LCM of 16, 24, 36, and 54 is 432.

The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

Explanation:

The LCM of four non-zero integers, a(16), b(24), c(36), and d(54), is the smallest positive integer m(432) that is divisible by a(16), b(24), c(36), and d(54) without any remainder.

Methods to Find LCM of 16, 24, 36, and 54

Let's look at the different methods for finding the LCM of 16, 24, 36, and 54.

  • By Listing Multiples
  • By Prime Factorization Method
  • By Division Method

LCM of 16, 24, 36, and 54 by Listing Multiples

The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

To calculate the LCM of 16, 24, 36, 54 by listing out the common multiples, we can follow the given below steps:

  • Step 1: List a few multiples of 16 (16, 32, 48, 64, 80 . . .), 24 (24, 48, 72, 96, 120 . . .), 36 (36, 72, 108, 144, 180 . . .), and 54 (54, 108, 162, 216, 270 . . .).
  • Step 2: The common multiples from the multiples of 16, 24, 36, and 54 are 432, 864, . . .
  • Step 3: The smallest common multiple of 16, 24, 36, and 54 is 432.

∴ The least common multiple of 16, 24, 36, and 54 = 432.

LCM of 16, 24, 36, and 54 by Prime Factorization

Prime factorization of 16, 24, 36, and 54 is (2 × 2 × 2 × 2) = 24, (2 × 2 × 2 × 3) = 23 × 31, (2 × 2 × 3 × 3) = 22 × 32, and (2 × 3 × 3 × 3) = 21 × 33 respectively. LCM of 16, 24, 36, and 54 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 24 × 33 = 432.
Hence, the LCM of 16, 24, 36, and 54 by prime factorization is 432.

LCM of 16, 24, 36, and 54 by Division Method

The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

To calculate the LCM of 16, 24, 36, and 54 by the division method, we will divide the numbers(16, 24, 36, 54) by their prime factors (preferably common). The product of these divisors gives the LCM of 16, 24, 36, and 54.

  • Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 16, 24, 36, and 54. Write this prime number(2) on the left of the given numbers(16, 24, 36, and 54), separated as per the ladder arrangement.
  • Step 2: If any of the given numbers (16, 24, 36, 54) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
  • Step 3: Continue the steps until only 1s are left in the last row.

The LCM of 16, 24, 36, and 54 is the product of all prime numbers on the left, i.e. LCM(16, 24, 36, 54) by division method = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 432.

☛ Also Check:

LCM of 16, 24, 36, and 54 Examples

  1. Example 1: Find the smallest number which when divided by 16, 24, 36, and 54 leaves 4 as the remainder in each case.

    Solution:

    The smallest number exactly divisible by 16, 24, 36, and 54 = LCM(16, 24, 36, 54) ⇒ Smallest number which leaves 4 as remainder when divided by 16, 24, 36, and 54 = LCM(16, 24, 36, 54) + 4

    • 16 = 24
    • 24 = 23 × 31
    • 36 = 22 × 32
    • 54 = 21 × 33

    LCM(16, 24, 36, 54) = 24 × 33 = 432

    ⇒ The required number = 432 + 4 = 436.

  2. Example 2: Which of the following is the LCM of 16, 24, 36, 54? 36, 5, 432, 24.

    Solution:

    The value of LCM of 16, 24, 36, and 54 is the smallest common multiple of 16, 24, 36, and 54. The number satisfying the given condition is 432. ∴LCM(16, 24, 36, 54) = 432.

  3. Example 3: Find the smallest number that is divisible by 16, 24, 36, 54 exactly.

    Solution:

    The value of LCM(16, 24, 36, 54) will be the smallest number that is exactly divisible by 16, 24, 36, and 54.
    ⇒ Multiples of 16, 24, 36, and 54:

    • Multiples of 16 = 16, 32, 48, 64, 80, 96, 112, 128, 144, 160, . . . ., 384, 400, 416, 432, . . . .
    • Multiples of 24 = 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, . . . ., 384, 408, 432, . . . .
    • Multiples of 36 = 36, 72, 108, 144, 180, 216, 252, 288, 324, 360, . . . ., 288, 324, 360, 396, 432, . . . .
    • Multiples of 54 = 54, 108, 162, 216, 270, 324, 378, 432, 486, 540, . . . ., 216, 270, 324, 378, 432, . . . .

    Therefore, the LCM of 16, 24, 36, and 54 is 432.

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The least number which when divided by 16, 24, 36 and 54 leaves in each case a remainder of 6 is

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The LCM of 16, 24, 36, and 54 is 432. To find the LCM of 16, 24, 36, and 54, we need to find the multiples of 16, 24, 36, and 54 (multiples of 16 = 16, 32, 48, 64 . . . . 432 . . . . ; multiples of 24 = 24, 48, 72, 96 . . . . 432 . . . . ; multiples of 36 = 36, 72, 108, 144 . . . . 432 . . . . ; multiples of 54 = 54, 108, 162, 216 . . . . 432 . . . . ) and choose the smallest multiple that is exactly divisible by 16, 24, 36, and 54, i.e., 432.

What is the Least Perfect Square Divisible by 16, 24, 36, and 54?

The least number divisible by 16, 24, 36, and 54 = LCM(16, 24, 36, 54)
LCM of 16, 24, 36, and 54 = 2 × 2 × 2 × 2 × 3 × 3 × 3 [Incomplete pair(s): 3]
⇒ Least perfect square divisible by each 16, 24, 36, and 54 = LCM(16, 24, 36, 54) × 3 = 1296 [Square root of 1296 = √1296 = ±36]
Therefore, 1296 is the required number.

Which of the following is the LCM of 16, 24, 36, and 54? 11, 432, 52, 5

The value of LCM of 16, 24, 36, 54 is the smallest common multiple of 16, 24, 36, and 54. The number satisfying the given condition is 432.

How to Find the LCM of 16, 24, 36, and 54 by Prime Factorization?

To find the LCM of 16, 24, 36, and 54 using prime factorization, we will find the prime factors, (16 = 24), (24 = 23 × 31), (36 = 22 × 32), and (54 = 21 × 33). LCM of 16, 24, 36, and 54 is the product of prime factors raised to their respective highest exponent among the numbers 16, 24, 36, and 54.
⇒ LCM of 16, 24, 36, 54 = 24 × 33 = 432.