The word is 'INVOLUTE'  (ii) Select two consonants out of 4. (iii) Arrange the five letters (3 vowels + 2 consonants) to form words. Number of permutations = 5! (iv) Apply fundamental principle of counting: Show
Number of words formed = = = 4 x 6 x 120 = 2880 216 Views Permutations and CombinationsHope you found this question and answer to be good. Find many more questions on Permutations and Combinations with answers for your assignments and practice. MathematicsBrowse through more topics from Mathematics for questions and snapshot. How many words, each of 3 vowels and 2 consonants, can be formed from the letters of the word ‘INVOLUTE’? How many words, each of 3 vowels and 2 consonants, can be formed from the letters of the word ‘INVOLUTE’? Answer : In the word ‘INVOLUTE’ there are 4 vowels, ‘I’,’O’,’U’ and ‘E’ and there are 4 consonants, ‘N’,’V’,’L’ and ‘T’. 3 vowels out of 4 vowels can be chosen in 4C3ways. 2 consonants out of 4 consonants can be chosen in 4C2 ways. Length of the formed words will be (3 + 2) = 5. So, the 5 letters can be written in 5! Ways. Therefore, the total number of words can be formed is = (4C3 X 4C2 X 5!) = 2880. How many words with or without meaning each of 3 vowels and 2 consonants can?Required number of ways =2880.
How many words each of 3 vowels and 2 consonants can be formed from the letters of the word equation?Therefore, the total number of words can be formed is = (4C3 X 4C2 X 5!) = 2880.
How many words each of 3 vowels and 2 consonants can be formed from the letters of the word daughter?Therefore, 30 words can be formed from the letters of the word DAUGHTER each containing 2 vowels and 3 consonants. Note: A Permutation is arranging the objects in order.
How many words may be formed with 3 consonants and 2 vowels so that no two consonants remain together?Number of groups, each having 3 consonants and 2 vowels = 210. Each group contains 5 letters. = 5! = 120.
|
