A person buys 8 oranges for Rs 15 and sells them at 10 for Rs 18 what does he gain or lose percent

Solution

C.P. Of 6 oranges, = Rs. 10 and C.P. of 1 orange =Rs.106=Rs.53S.P. of 4 oranges =Rs.9and S.P of 1 orange =Rs.94∴Gain = S.P - C.P.= Rs.94−Rs.53=27−2012=Rs.712Gain%=Gain×100C.P.=712×10053=7×100×312×5=35% Ans.

A man buys 8 oranges for a rupee and sell 6 oranges for a rupee. What is the profit percentage?

This question was previously asked in

SSC MTS Previous Paper 40 (Held On: 16 September 2017 Shift 1)

View all SSC MTS Papers >

  1. 25
  2. 20
  3. 33.33
  4. 10

Answer (Detailed Solution Below)

Option 3 : 33.33

Free

CT : GK (Ancient History)

10 Questions 10 Marks 6 Mins

Cost price of 8 oranges = Rs. 1

Cost price of 1 orange = Rs. (1/8)

∴ Cost price of 6 oranges = Rs. (6/8) = Rs. (3/4)

Given,

Selling price of 6 oranges = Rs. 1

∴ Profit percentage= [(selling price – cost price)/cost price] × 100

= [(1 – ¾)/(3/4)] × 100

= 33.33%

Last updated on Sep 28, 2022

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